Здравствуйте. Подскажите пожалуйста можно как-нибудь “упростить” условие?
if “1” in a or “2” in “a” or “3” in a or “4” in a or “5” in a or “6” in a or “7” in a…:
pass
else:
pass
for x in map(str, range(1,8)):
if x in a: pass
else: pass
any( map(lambda x:str(x) in a, xrange(1,8)) )
>>> s = 'abcd1defg2hijk'
>>> set(s) & set("1234567890")
{'1', '2'}
>>> set(s) & set("34567890")
set()
>>>
if any( c in a for c in '0123456789'):
pass
if any('0'<=c<='9' for c in a):
pass