Python-сообщество

>python3
Python 3.4.0a3+ (default:2e8c424dc638, Oct 15 2013, 22:30:15) 
[GCC 4.8.1] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> lst = str(input("Введіть числа:")).split(" ")
Введіть числа:4 5 6
>>> print(lst)
['4', '5', '6']
>>> 

k=int(1)
magic=1
s=0
b=[0,0,0,0,0,0,0,0,0,0]
a=str(input()).split(" ")
b[int(a[len(a)-1])]=b[int(a[len(a)-1])]+1
for i in range(len(a)-2,-1,-1)
        for j in range((int(a[i])+1),10):
            if b[j]>0:
               s=s+(magic*b[j])/(b[int(a[i])]+1)
        b[int(a[i])]=b[int(a[i])]+1
        k=k+1
        magic=magic*k/(b[int(a[i])])
print ("%d" % (s)) 

# coding: utf8
s = raw_input("введите числа:" )
a = []
for i in s:
    a.append(i)
for i in a:
    try:
        a.remove(" ")
    except ValueError:
        pass
print len(a)

# coding: utf8
s = raw_input("введите числа:" )
a = s.split()
print len(a)

k = 1
magic = 1
s = 0
a = list( map(int, input().split(" ")) )
b = [0] * (max(a) + 1)
b[a[-1]] += 1
for i in range(len(a)-2,-1,-1):
        print(i)
        for j in range(a[i]+1, len(b)):
            if b[j] > 0:
               s = s + (magic * b[j]) / (b[a[i]] + 1)
        b[a[i]] += 1
        k += 1
        magic = magic * k / b[a[i]]
print(s)