urls = urls.xpath('//img/parent::a[not(re:match(@href, "(slovo)")) ]/@href', namespaces={"re": "http://exslt.org/regular-expressions"})

<li>
<a href="/url/link.html" title="title"><span class="image"><img src="http://domain.com/1.jpg" alt="alt"></span><span class="title">title</span></a>
</li>

a[img or span/img]//img[...]