password = ['oftiiiomue', 'vvveqbryd5', 'xveeevk6i7', 'llot7ju79c', 'opu5xzppmb', 'tjyt5sghmm', 'ok5yx77wvn', '0yctvllrer', 'bbgea92ekn', 'gwfpqqhske', 'bzibsmmzlo']
def check2(i):
    if i[0] == i[1]:
        return 2
    if i[1] == i[2]:
        return 2
    if i[2] == i[3]:
        return 2
    if i[3] == i[4]:
        return 2
    if i[4] == i[5]:
        return 2
    if i[5] == i[6]:
        return 2
    if i[6] == i[7]:
        return 2
    if i[7] == i[8]:
        return 2
    if i[8] == i[9]:
        return 2
def check3(i):
    if i[0] == i[1] and i[1] == i[2]:
        return 3
    if i[1] == i[2] and i[2] == i[3]:
        return 3
    if i[2] == i[3] and i[3] == i[4]:
        return 3
    if i[3] == i[4] and i[4] == i[5]:
        return 3
    if i[4] == i[5] and i[5] == i[6]:
        return 3
    if i[5] == i[6] and i[6] == i[7]:
        return 3
    if i[6] == i[7] and i[7] == i[8]:
        return 3
    if i[7] == i[8] and i[8] == i[9]:
        return 3
for i in password:
    if check2(i) != None:
        print 'check2', i
    if check3(i) != None:
        print 'check3', i

password = ['oftiiiomue', 'vvveqbryd5', 'xveeevk6i7', 'llot7ju79c', 'opu5xzppmb', 'tjyt5sghmm', 'ok5yx77wvn', '0yctvllrer', 'bbgea92ekn', 'gwfpqqhske', 'bzibsmmzlo']
def check_dup(passw):
    x = tmp = 0
    while x < len(passw):
        if tmp == passw[x]:
            return True
        tmp = passw[x]
        x +=1
    return False
for x in password:
    print x, check_dup(x)

oftiiiomue True
vvveqbryd5 True
xveeevk6i7 True
llot7ju79c True
opu5xzppmb True
tjyt5sghmm True
ok5yx77wvn True
0yctvllrer True
bbgea92ekn True
gwfpqqhske True
bzibsmmzlo True

from collections import deque
from itertools import takewhile
    
def check_dup_n(passw, n=2):
    i = 0
    acc = deque()
    while i < len(passw):
        char = passw[i] 
        dup = list(takewhile(lambda x: x == char, reversed(acc) ))
        if len(dup) >= n:
            return dup[0]
        if len(acc) >= n : 
            acc.popleft()
        acc.append(char)
        i += 1
    return False

oftiiiomue

oftiiomue

oftiiiomme

import re
from collections import Counter
password = ['oftiiiomue', 'vvveqbryd5', 'xveeevk6i7', 'llot7ju79c', 'opu5xzppmb', 'tjyt5sghmm', 'ok5yx77wvn', '0yctvllrer', 'bbgea92ekn', 'gwfpqqhske', 'bzibsmmzlo']
for w in password:
    c = Counter(w)
    letters = [x[0] for x in c.most_common() if x[1] > 1]
    for l in letters:
        s = [x for x in re.findall(r'(%s*)' % l, w) if len(x) > 1]
        if s:
            print "%s => %s %s раз" % (w, s[0][0], len(s[0]))

from itertools import groupby
password = ['oftiiiomue', 'vvveqbryd5', 'xveeevk6i7', 'llot7ju79c', 'opu5xzppmb', 'tjyt5sghmm', 'ok5yx77wvn', '0yctvllrer', 'bbgea92ekn', 'gwfpqqhske', 'bzibsmmzlo']
for p in password:
    print(sorted(((len(s), s[0] ) for s in (tuple(kv[1]) for kv in groupby(p))), key=lambda x: x[0], reverse=True))

import re
password = ['oftiiiomue', 'vvveqbryd5', 'xveeevk6i7', 'llot7ju79c', 'opu5xzppmb', 'tjyt5sghmm', 'ok5yx77wvn', '0yctvllrer', 'bbgea92ekn', 'gwfpqqhske', 'bzibsmmzlo']
for pasw in password:
    for letter, length in re.findall(r'(\w)(\1+)', pasw):
        print pasw, letter, len(length)+1