Python-сообщество

# google
>

 > picasa list-albums title
Альбом 1
Альбом 2

 >

import subprocess

proc = subprocess.Popen("google", shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE,)


print "First call ======================="

stdout_value, stderr_value = proc.communicate(input="picasa list-albums title")
print 'Out:\n', stdout_value
print 'Error:\n', repr(stderr_value)

print "Second call ======================="

stdout_value, stderr_value = proc.communicate(input="picasa list-albums title")
print 'Out:\n', repr(stdout_value)
print 'Error:\n', repr(stderr_value)

C:\Documents and Settings\KurchavyA\Рабочий стол\Новая папка\googlecl-0.9.9\goog
lecl-0.9.9>c:\python25\python.exe pp.py
First call =======================
Out:  
> Альбом 1
Альбом 2
>

Error:  ''
Second call =======================
Traceback (most recent call last):
  File "pp.py", line 16, in <module>
    stdout_value, stderr_value = proc.communicate(input="picasa list-albums titl
e")
  File "c:\python25\lib\subprocess.py", line 670, in communicate
    return self._communicate(input)
  File "c:\python25\lib\subprocess.py", line 891, in _communicate
    self.stdin.write(input)
ValueError: I/O operation on closed file