Python-сообщество

 
from __future__ import division
from sympy import *
x, y, z, t = symbols('x y z t')
k, m, n = symbols('k m n', integer=True)
f, g, h = symbols('f g h', cls=Function)
In [1]: residue(tanh(x), x, 3*I*pi/2)
---------------------------------------------------------------------------
PoleError                                 Traceback (most recent call last)
/.../.../<ipython-input-1-06ae92309a12> in <module>()
----> 1 residue(tanh(x), x, 3*I*pi/2)
/usr/lib/python2.7/dist-packages/sympy/series/residues.pyc in residue(expr, x, x0)
     43     if x0 != 0:
     44         expr = expr.subs(x, x+x0)
---> 45     s = expr.series(x, 0, 0).removeO()
     46     # TODO: this sometimes helps, but the series expansion should rather be
     47     # fixed, see #1627:
/usr/lib/python2.7/dist-packages/sympy/core/expr.pyc in series(self, x, x0, n, dir)
   1560 
   1561         if n != None: # nseries handling
-> 1562             s1 = self._eval_nseries(x, n=n, logx=None)
   1563             o = s1.getO() or S.Zero
   1564             if o:
/usr/lib/python2.7/dist-packages/sympy/core/function.pyc in _eval_nseries(self, x, n, logx)
    378                 term = e.subs(x, S.Zero)
    379                 if term.is_bounded is False or term is S.NaN:
--> 380                     raise PoleError("Cannot expand %s around 0" % (self))
    381                 series = term
    382                 fact = S.One
PoleError: Cannot expand tanh(x + 3*I*pi/2) around 0 

In [2]: residue(tan(x), x, 3*pi/2)
Out[2]: -1