Есть функция которая возвращает 3 массива:
def test(): number = [1,2,3,4,5] symbols = ["q","w","e","r","t"] zero = [0,0,0,0,0] return number, symbols, zero
нужно что бы данные вывелись в таком формате
1
q
0
2
w
0
3
e
0
def test(): number = [1,2,3,4,5] symbols = ["q","w","e","r","t"] zero = [0,0,0,0,0] return number, symbols, zero
>>> list(zip([1, 2, 3], 'abc', [0, 0, 0])) [(1, 'a', 0), (2, 'b', 0), (3, 'c', 0)] >>>
>>> sum(zip([1, 2, 3], 'abc', [0, 0, 0]), ()) (1, 'a', 0, 2, 'b', 0, 3, 'c', 0) >>>
for i, g, x in zip(number, symbols, zero): print(i) print(g) print(x)