Python-сообщество

 a = '1 3 2'
for x in a.split():
    print(int(x))

 >>> doc = '''1 3 2
2 1 2
2 5 1 
1 3 4
6 1 1'''
>>> a =[sorted([int(j) for j in i.split()]) for i in doc.split('\n')]
>>> a
[[1, 2, 3], [1, 2, 2], [1, 2, 5], [1, 3, 4], [1, 1, 6]]
>>> a0 = sorted([i[0] for i in a])
>>> a0
[1, 1, 1, 1, 1]
>>> t = sorted([i[1] for i in a] + [i[2] for i in a])
>>> t
[1, 2, 2, 2, 2, 3, 3, 4, 5, 6]
>>> for i in t:
	s= sum(a0)
	if s%5:
		print(a0,s)
		break
	a0[-1] = i
	
[1, 1, 1, 1, 2] 6

 >>> st = [(1, 2, 3), (1, 2, 2), (1, 2, 5), (1, 3, 4), (1, 1, 6)]
>>> s = { (x, y, z) for x, _, _ in st for _, y, _ in st for _, _, z in st if sum((x,y,z))%5 }
>>> s
set([(1, 2, 6), (1, 3, 2), (1, 1, 6), (1, 2, 3), (1, 3, 5), (1, 1, 4), (1, 2, 4), (1, 3, 4), (1, 1, 5), 
(1, 1, 2), (1, 2, 5), (1, 3, 3)])
>>> min(s, key=sum)
(1, 1, 2)
>>> sum(min(s, key=sum))
4

 >>> st = [(1, 2, 3), (1, 2, 2), (1, 2, 5), (1, 3, 4), (1, 1, 6)]
>>> sum(min([ x for x in st if sum(x)%5 ], key=sum))
6