Python-сообщество

Mikhail911 · Фев. 15, 2019 08:52:33

доброго дня всем!
Я тут задачку решал. Опыт не большой, кажется код получился не совсем. Может расскажите как бы вы его написали или упростили. Спасибо заранее.

задача :

likes // must be “no one likes this”
likes // must be “Peter likes this”
likes // must be “Jacob and Alex like this”
likes // must be “Max, John and Mark like this”
likes // must be “Alex, Jacob and 2 others like this”

мое решение:

def likes(n):
if len(n) == 0:
return “no one likes this”
elif len(n) == 1:
a = (n + “ ” + “likes this”)
return(a)
elif len(n) == 2:
b = (n + “ ” + “and” + “ ” + n + “ ” + “like this”)
return b
elif len(n) == 3:
c = (n + “,” + “ ” + n + “ ” + “and” + “ ” + n + “ ” + “like this”)
return c
elif len(n) >= 4:
d = (n + “,” + “ ” + n + “ ” + “and” + “ ” + str(len(n)) + “ ” + “others like this”)
return d

py.user.next · Фев. 15, 2019 09:49:52

  
>>> def likes(lst):
...     length = len(lst)
...     if length == 0:
...         return '{} likes this'.format('no one')
...     elif length == 1:
...         return '{} likes this'.format(lst[0])
...     elif length == 2:
...         return '{} and {} like this'.format(*lst)
...     elif length == 3:
...         return '{}, {} and {} like this'.format(*lst)
...     else:
...         return '{}, {} and {} others like this'.format(
...             lst[0], lst[1], len(lst) - 2)
... 
>>> likes([])
'no one likes this'
>>> likes(['Peter'])
'Peter likes this'
>>> likes(['Jacob', 'Alex'])
'Jacob and Alex like this'
>>> likes(['Max', 'John', 'Mark'])
'Max, John and Mark like this'
>>> likes(['Alex', 'Jacob', 'Peter', 'Max'])
'Alex, Jacob and 2 others like this'
>>>

Python-сообщество

Уведомления

#1 Фев. 15, 2019 08:52:33

Задачка Codewars

#2 Фев. 15, 2019 09:49:52

Задачка Codewars

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