Python-сообщество

 def number_phone(n):
    all_numbers = ["1", "2", "3", "4", "5", "6", "7", "8", "9", "0"]
    flag_one = False
    flag_two = False
    flag_three = False
    for i in range(n):
        phone_number = input() # (123)-123-12-12
        if phone_number[0] == "(" and phone_number[4] == ")":
            flag_one = True
        else:
            return "Error"
        if phone_number[1:4] and phone_number[6:9] and phone_number[10:12] and phone_number[13:-1] in all_numbers:
            flag_two = True
        else:
            return "Error"
        if phone_number[5] == "-" and phone_number[9] == "-" and phone_number[12] == "-":
            flag_three = True
    if flag_one == flag_two == flag_three == True:
        return "Номер введен верно"
    else:
        return "Номер введен неверно"
print(number_phone(2))

 def check_phone(ptn, line):
    if len(ptn) != len(line):# если длина разная False
        return False
    for i, p in zip(line, ptn): # сравниваем поэлементно с шаблоном
        if i == p or p == 'x' and i.isdigit():
            print(i,'<>', p, '   ok')
            continue
        else:
            print(i, '&', p, '-> bad')
            return False
    return True
#
l = '(123) 123-1210'
#
res = check_phone('(xxx) xxx-xxxx', l)
print('______\nres = ', res)
print('=========================')
l2 = '123-1a3-1210'
res2 = check_phone('xxx-xxx-xxxx', l2)
print(res2)

( <> (    ok
1 <> x    ok
2 <> x    ok
3 <> x    ok
) <> )    ok
  <>      ok
1 <> x    ok
2 <> x    ok
3 <> x    ok
- <> -    ok
1 <> x    ok
2 <> x    ok
1 <> x    ok
0 <> x    ok
______
res =  True
=========================
1 <> x    ok
2 <> x    ok
3 <> x    ok
- <> -    ok
1 <> x    ok
a & x -> bad
False

Process finished with exit code 0