b=[(0 and 1 and 2),(6 and 7 and 8),(2 and 4 and 6)]
a=[1,2,3,4,5,6,8,9,0]
def logic():
    for i in range(3):
        if b[i] in a:
            print ("b in a")
        else:
            print ("b isn't in a")
logic()

>>> b=[(0 and 1 and 2),(6 and 7 and 8),(2 and 4 and 6)]
>>> b
[0, 8, 6]

>>> {0, 8}.issubset(set(b))
True

>>> 0 in b and 8 in b
True

>>> all(elem in b for elem in [0, 8])
True

b=[(0 and 1 and 2),(6 and 7 and 8),(2 and 4 and 6)]
a=[1,2,3,4,5,6,8,9,0]
def logic(a, b):
    return all(elem in a for elem in b)  
if logic(a, b):
    print ("b in a")
else:
    print ("b isn't in a")