# Формирование списков
    data_year_2_sorted_adult = []
    data_year_2_sorted_children = []
    data_changes_sorted_adult = []
    data_changes_sorted_children = []
    tmp = []
    for rec in data:
        d_class = rec[0]
        value1 = rec[i_year1]
        value2 = rec[i_year2]
        d_change = (value2 - value1) / value1 * 100
        record = dict(theclass=d_class, value=value2, change=d_change,
                      age=rec[-1])
        tmp.append(record)
    for rec in sorted(tmp, key=lambda d: d['value'], reverse=True):
        record = {rec['theclass']: round(rec['value'], ndigits=2)}
        if rec['age'] == ADULTS:
            data_year_2_sorted_adult.append(record)
        elif rec['age'] == CHILDREN:
            data_year_2_sorted_children.append(record)
        else:
            raise NoSuchYearError("Неверный возраст!")
    for rec in sorted(tmp, key=lambda d: d['change'], reverse=True):
        record = {rec['theclass']: round(rec['change'], ndigits=2)}
        if rec['age'] == ADULTS:
            data_changes_sorted_adult.append(record)
        elif rec['age'] == CHILDREN:
            data_changes_sorted_children.append(record)
        else:
            raise NoSuchYearError("Неверный возраст!")

  
>>> import json
>>> import collections
>>> 
>>> d = collections.OrderedDict()
>>> d['c'] = 3
>>> d['b'] = 2
>>> d['a'] = 1
>>> 
>>> json.dumps(d)
'{"c": 3, "b": 2, "a": 1}'
>>> 

  
>>> dct = {'x' : [{'a': 4},
...               {'b': 3},
...               {'c': 2},
...               {'d': 1}]}
>>> 
>>> 
>>> dct
{'x': [{'a': 4}, {'b': 3}, {'c': 2}, {'d': 1}]}
>>> 
>>> dct['x'].sort(key=lambda d: tuple(d.values())[0])
>>> dct
{'x': [{'d': 1}, {'c': 2}, {'b': 3}, {'a': 4}]}
>>>

  
>>> d = {'a': 4, 'b': 3, 'c': 2, 'd': 1}
>>> 
>>> out = dict(sorted(d.items(), key=lambda i: i[1]))
>>> out
{'d': 1, 'c': 2, 'b': 3, 'a': 4}
>>> 
>>> for i, j in zip(d, out):
...   print('d:', i, '->', d[i], 'out:', j, '->', out[j]) 
... 
d: a -> 4 out: d -> 1
d: b -> 3 out: c -> 2
d: c -> 2 out: b -> 3
d: d -> 1 out: a -> 4
>>>