a = ['asdf','qwer']
b = ['jl','asdf','sfsdf','qwer','joiji']
У меня получилось только вот так:
def mass(a,b):
k = 0
for i in a:
if i in b:
k = 1
else:
return 0
return k
a = ['asdf','qwer']
b = ['jl','asdf','sfsdf','qwer','joiji']
def mass(a,b):
k = 0
for i in a:
if i in b:
k = 1
else:
return 0
return k
result = not (set(a)-set(b))
result = not set(a).difference(b)
IsemСпасибо! то что нужно….илиresult = not (set(a)-set(b))result = not set(a).difference(b)
>>> a = ['asdf','qwer']
>>> b = ['jl','asdf','sfsdf','qwer','joiji']
>>> set(a).issubset(b)
True
>>>
>>> a = ['asdf','qwer']
>>> b = ['jl','asdf','sfsdf','qwer','joiji']
>>> set(a) < set(b)
True
>>>