Вод код с openpyxl:
from openpyxl import load_workbook
wb = load_workbook('Shablon.xlsx')
print (wb.get_sheet_names())
wb = load_workbook('r.xlsx ')
print (wb.get_sheet_names())
Я так понимаю он не может второй открыть, т.к. первый не закрыт:
['Лист1']
Traceback (most recent call last):
File "C:\My PY G\Buh111\excel222.py", line 8, in <module>
wb = load_workbook('r.xlsx ')
File "C:\Program Files\Python36\lib\site-packages\openpyxl\reader\excel.py", line 171, in load_workbook
archive = _validate_archive(filename)
File "C:\Program Files\Python36\lib\site-packages\openpyxl\reader\excel.py", line 108, in _validate_archive
raise InvalidFileException(msg)
openpyxl.utils.exceptions.InvalidFileException: openpyxl does not support .xlsx file format, please check you can open it with Excel first. Supported formats are: .xlsx,.xlsm,.xltx,.xltm
>>>
А как закрыть - не понимаю.