Разобрался
строка строка подкл.
cnopts = pysftp.CnOpts()
cnopts.hostkeys = None
sftp = pysftp.Connection(host, username='user', password='c3^98fiXS&', cnopts=cnopts)
вот код поиска
def delete_old_files(path_del_files, copies_for_delete, extension_for_files):
#
# Delete old archives copies in log_dir and path.
#
min_del_dict = ''
if copies_for_delete > saved_archive_copies:
while copies_for_delete > saved_archive_copies:
del_dict = {}
sftp.chdir(path_del_files)
dir_list_folder = sftp.listdir()
for files in dir_list_folder:
if sftp.isfile(files):
if fnmatch.fnmatch(files, extension_for_files) or fnmatch.fnmatch(files, extension_for_files):
date = sftp.stat(files).st_mtime
del_dict[files] = date
min_del_dict = min(del_dict, key=del_dict.get)
copies_for_delete -= 1
sftp.remove(min_del_dict)
sftp.chdir('/')
return min_del_dict
return 'Logs and backups files less or equal 5'
Может пригодится кому-то. Или кто более опытен поможет сократить саму функцию